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4. What approximate value should come in place of the question

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4. SIMPLIFICATION
BODMAS RULE :
B = Bracket
→ ( ), { }, []
→(1)
O = Of
→x
→(2)
D = Division
→÷
→(3)
M = Multiplication
→x
→(4)
A = Addition
→+
→(5)
S = Subtraction
→-
→ (6)
Problems:
1.
18800 ÷ 470 ÷20
Sol :
18800 ÷ 470 ÷20
=
18800
470
÷ 20 = 40 ÷ 20 = 2
Ans : 2
2.
1
2
5
108 ÷ 36 of 4 +
1
x 34
Sol :
1
108 ÷ 36 of 4 +
1
=108 ÷36 x4 +
=
108
9
+
2
5
x
2
5
2
5
1
x 34
1
x 34
13
4
13
= 12 + 10
=
120+13
10
=
Ans :
3.
=
1
3
5
133
=
10
3
13 10
1
4
x
3
5
÷ +
1
4
x
÷3 +
3
13.3 (or) 13 10
2
5
-
of
5
7
2
5
5
7
Solu :
1
3
5
3
3
5
- of
1
3
5
3
2
5
1
3
1
3
=3 x 5+ 4 x 55
1
3
2
= 3+ 4 x 5- 5
4+3 2
7
2
=
- =
20
7
20
7
49−40
9
= 140 = 140
÷ +
1
4
x
3
5
5
7
2
5
- x
9
Ans :140
4.
3.5 ÷ 0.7 of 7 + 0.5 x 0.3 -0.1
Sol :
3.5 ÷ 0.7 of 7 + 0.5 x 0.3 – 0.1
3.5 ÷ 0.7 x 7 + 0.5 x 0.3 – 0.1
3.5
4.9
+ 0.5 x 0.3 – 0.1
5
=7 + 0.5 x 0.3 – 0.1
5
=7 + 0.15 – 0.1
5
15
1
=7 + 100 - 10 =
=
500+105
700
605− 70
700
1
605
1
- 10 = 700 - 10
=
535
700
=
107
140
= 0.764
Ans : 0.764
5.
Which number should replace both the question marks in the
following equation ?
?
432
=
243
?
1) 308
2) 312 3) 324 4) 316 5)None of these
(State bank of India,2008)
Ans : (3)
Sol :
?= 432  243
= 2  2  2  2  3  3  3  3  3  3  3 3
= 2 x 2 x 3 x 3 x3 x 3 =234
6.
What approximate value should come in place of the question mark (?)
in the following questions. (you are not expected to calculate the exact
value .)
2341.9823 + 18625.1372 + 6225.1689 + 9218
1) 30554
Ans :
2) 28136
3) 32612
4) 35218
5) 29828
(Allahabad bank, 2007)
(1)
Sol :
Given value =2342 + 18625 + 6225 +3352 =30554
7.
14.082 x 19.964 x 23.980 = ?
1) 6220
2) 5820 3) 6742 4) 5932 5) 6986
(Allahabad bank,2007)
Ans :
(3)
Sol :
14.082 x 19.964 x 23.980 = 14 x 20 x 24 (As the choice are not
very close, we can make such changes.)
= 6720 = 6742
8.
1
6
3
18 + 17 + 35= ?
121
163
1) 8140
2) 6280
197
3) 9280
117
4) 7140
5) None of these
(Allahabad bank,2007)
Ans :
Sol :
(2)
1
6
3
1
6
3
18 + 17 + 35 = 5 + ( 8 + 7 + 5)
=5+ +(
9.
35+240+168
)
280
Simplify : 1 +
443
1
1
1+
1
1+
1
1+
3
Sol :
163
= 5 + ( 280 ) = 6 ( 280 )
starting from the bottom
1
1 +1
1
1
=1+
1+
1+
1
1+
3
1+
4
3
4
1
1
=1+
1+
7
4
=1+
1
4
=1+
=
1
11
1+
7
=1 +
7
11
=
7
18
11
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